#include <cstdio>
#include <cstring>
#include <algorithm>
#include <iostream>
using namespace std;
typedef long long ll;
const int maxn = 1000005;
bool is_prime[maxn];
bool is_prime_small[maxn];
ll prime[maxn];
ll prime_num=0;

//对区间[a,b)内的整数执行筛法，is_prime[i-a]=true  ---  表示i是素数 注意这里下标偏移了a，所以从0开始。
void segment_sieve(ll a,ll b) {
    for(ll i=0;i*i<=b;++i) is_prime_small[i]=true; //对[2,sqrt(b))的初始化全为质数
    for(ll i=0;i<=b-a;++i) is_prime[i]=true; //对下标偏移后的[a,b)进行初始化

    for(ll i=2;i*i<=b;++i) {
        if(is_prime_small[i]) {
            for(ll j=2*i;j*j<=b;j+=i) is_prime_small[j]=false;  //筛选[2,sqrt(b));
            //(a+i-1)/i得到最接近a的i的倍数，最低是i的2倍，然后筛选
            for(ll j=max(2LL,(a+i-1)/i)*i;j<=b;j+=i) is_prime[j-a]=false;
        }
    }
    for(ll i=0;i<=b-a;++i)  //统计个数
        if(is_prime[i]) prime[prime_num++]=i+a;
}

int main()
{
    ll a,b,ans1,ans2,ans3,ans4,dis1,dis2;
    while(~scanf("%lld%lld",&a,&b))
    {
        if(a==1)
            a++;
        prime_num=0;
        dis1 = 0;
        dis2 =  1000010;
        memset(prime,0,sizeof(prime));
        segment_sieve(a,b);
        for(ll i=1;i<prime_num;++i)
        {
            //printf("%d",prime[i]);
            if(prime[i]-prime[i-1]>dis1)
            {
                dis1 = prime[i]-prime[i-1];
                ans1 = prime[i-1];
                ans2 = prime[i];
            }
            if(prime[i]-prime[i-1]<dis2)
            {
                dis2 = prime[i]-prime[i-1];
                ans3 = prime[i-1];
                ans4 = prime[i];
            }
        }
        //cout<<prime_num<<endl;
        if(dis1==0)
            printf("There are no adjacent primes.\n");
        else
            printf("%lld,%lld are closest, %lld,%lld are most distant.\n",ans3,ans4,ans1,ans2);
        //printf("%lld\n",prime_num);
    }
    return 0;
}