Let the Balloon Rise map一个数组
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.
This year, they decide to leave this lovely job to you.
InputInput contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
OutputFor each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input
1、阅读提问3
2、放大镜特效
3、发现一句实话
4、maven中的groupId和artifactld到底指的什么？
5、常用排序算法比较
This year, they decide to leave this lovely job to you.
InputInput contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
OutputFor each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input
5 green red blue red red 3 pink orange pink 0Sample Output
red pink
代码：
#include <iostream> #include <cstdio> #include <queue> #include <map> using namespace std; int main() { int n; string a,max="a"; map<string,int> b; while(scanf("%d",&n)&&n) { b[max]=0; for(int i=1;i<=n;i++) { cin>>a; b[a]++; if(b[a]>b[max])max=a; } cout<<max<<endl; } }优质内容筛选与推荐>>
1、阅读提问3
2、放大镜特效
3、发现一句实话
4、maven中的groupId和artifactld到底指的什么？
5、常用排序算法比较